Question

1) 3(R+10) + 200 = 236​

Answer 1

Answer:

3R+30=36. USE THIS FORMULA

Answer 2

Given:

Consider the given equation 3(R+10) + 200 = 236

Find:

The value of R

Solution:

Subtract 200 from both the sides in the given equation

3(R+10) + 200 - 200 = 236 - 200

3(R+10) = 36

Divide both the sides by 3

R + 10 = 36/3

R + 10 = 12

Subtract 10 from both the side

R = 2

Hence the answer is 2.