Question

(1/3)rd the diagonal of a square is 2. What is the measure of the side of the concerned square?

Answer 1

3root2 is the answer

Answer 2

Answer:

$3\sqrt{2}$

Step-by-step explanation:

Let the diagonal of the square be x

We are given that (1/3)rd the diagonal of a square is 2.

So, $\frac{1}{3}x=2$

$x=6$

So, diagonal of square is 6

Formula of diagonal of square = $\sqrt{2}a$

Where a is the side of square

$\sqrt{2}a=6$

$a=\frac{6}{\sqrt{2}}$

$a=3\sqrt{2}$

Hence The side of square is  $3\sqrt{2}$