Question

1/3-root8+1/root7-root6+1/root5-2-1/root8-root7-1/root6-root5=5

Answer 1

1/(3-√8) + 1/(√7-√6) + 1/(√5 -2) -1/(√8-√7) -1/(√6-√5)

use concept of rationalisation,

1/(3-√8) = 3+√8

1/(√7 -√6) = √7+√6

1/(√5-2) = √5+2

1/(√8-√7) = √8+√7

1/(√6-√5) = √6 +√5

put all of this ,

now,

3+√8 +√7+√6 +√5+2-√8 -√7 -√6 -√5

= 5
hence proved

Answer 2

Answer:

√7) -1/(√6-√5)

√7) -1/(√6-√5)use concept of rationalisation,

√7) -1/(√6-√5)use concept of rationalisation,1/(3-√8) = 3+√8

√7) -1/(√6-√5)use concept of rationalisation,1/(3-√8) = 3+√81/(√7 -√6) = √7+√6

√7) -1/(√6-√5)use concept of rationalisation,1/(3-√8) = 3+√81/(√7 -√6) = √7+√61/(√5-2) = √5+2

√7) -1/(√6-√5)use concept of rationalisation,1/(3-√8) = 3+√81/(√7 -√6) = √7+√61/(√5-2) = √5+21/(√8-√7) = √8+√7

√7) -1/(√6-√5)use concept of rationalisation,1/(3-√8) = 3+√81/(√7 -√6) = √7+√61/(√5-2) = √5+21/(√8-√7) = √8+√71/(√6-√5) = √6 +√5

√7) -1/(√6-√5)use concept of rationalisation,1/(3-√8) = 3+√81/(√7 -√6) = √7+√61/(√5-2) = √5+21/(√8-√7) = √8+√71/(√6-√5) = √6 +√5put all of this ,

√7) -1/(√6-√5)use concept of rationalisation,1/(3-√8) = 3+√81/(√7 -√6) = √7+√61/(√5-2) = √5+21/(√8-√7) = √8+√71/(√6-√5) = √6 +√5put all of this ,now,

√7) -1/(√6-√5)use concept of rationalisation,1/(3-√8) = 3+√81/(√7 -√6) = √7+√61/(√5-2) = √5+21/(√8-√7) = √8+√71/(√6-√5) = √6 +√5put all of this ,now,3+√8 +√7+√6 +√5+2-√8 -√7 -√6 -√5

√7) -1/(√6-√5)use concept of rationalisation,1/(3-√8) = 3+√81/(√7 -√6) = √7+√61/(√5-2) = √5+21/(√8-√7) = √8+√71/(√6-√5) = √6 +√5put all of this ,now,3+√8 +√7+√6 +√5+2-√8 -√7 -√6 -√5= 5

√7) -1/(√6-√5)use concept of rationalisation,1/(3-√8) = 3+√81/(√7 -√6) = √7+√61/(√5-2) = √5+21/(√8-√7) = √8+√71/(√6-√5) = √6 +√5put all of this ,now,3+√8 +√7+√6 +√5+2-√8 -√7 -√6 -√5= 5hence proved

√7) -1/(√6-√5)use concept of rationalisation,1/(3-√8) = 3+√81/(√7 -√6) = √7+√61/(√5-2) = √5+21/(√8-√7) = √8+√71/(√6-√5) = √6 +√5put all of this ,now,3+√8 +√7+√6 +√5+2-√8 -√7 -√6 -√5= 5hence provedRead more on Brainly.in - https://brainly.in/question/1120589#readmore