Question

(1) 3/x-1 + 1/x-3 = 4/x-2​

Answer 1

$\huge \sf {\orange {\underline {\pink{\underline {A᭄ɴsᴡᴇʀ࿐ :−}}}}}$

$\frac{3}{x - 1} + \frac{1}{x - 3} =\frac{4}{x - 2} \\ \frac{3(x - 3) + 1(x - 1)}{(x - 1)( x- 3)} = \frac{4}{x - 2} \\ 3x-9 + x-1 / (x-1)(x-3) = 4/ x-2 \\ (4x -10) (x-2) = 4 (x-1) (x-3) \\ 4×2 – 8x -10x+20= 4 (x {}^{2}  -3x -x+3) \\ 4x {}^{2}  -18x +20 = 4x {}^{2} – 12x -4x +12 \\4x {}^{2}  -18x +20 = 4x {}^{2} – 16x +12 \\ - 18x +20 = – 16x +12 \\ -18x+16x = 12 – 20 \\ - 2x = -8 \\ 2x = 8 \\ \boxed{ \red{x = \cancel \frac{8}{2} = 4}}$

Answer 2

Answer: 3/x-1+1/x-3=4/x-2

3(x-3)+1(x-1)/(x-1)(x-3)=4/x-2

3x-9+x-1/(x-1)(x-3)=4/x

(4x-10)(x-2)=4(x-1)(x-3)

4×2-8x-10x+20=4(x²-3x-x+3)

4x²-18x+20=4x²-12x-4x+12

4x²-18x+20=4x²-16x+12

-18x+20=-16x+12

-18x+16x=12-20

-2x=-8

2x=8

x=8/2

x=4