Question

1/3^x = 9^kx. find the value of k​

Answer 1

Step-by-step explanation:

1/3^x = 9^kx

3^-x = 3^2kx

2kx = - x

k = -1/2

Answer 2

Answer:

$\frac{1}{3} ^{x} = 9 ^{kx}$

$3 ^{ - x} = 3 ^{2kx}$

Equate powers

$- x = 2kx$

Divide both sides by 2x

$\frac{ - x}{2x} = \frac{2kx}{2x}$

$k = \frac{ - 1}{2}$