(1+3/x)(9/x²-9+1) factorise the following
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(1+3/x) {(3/x) ^2-(3)^2+1}
(1+3/x) (3/x+2) (3/x-2) +1
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(1+3/x)(9/x²-9+1)
= (1+3/x)(3/x-1)
= (3/x+1)(3/x-1)
= (3/x)²-(1)²
= 9/x²-1
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