Question

1/3(x+y)+2z=21, 3x-1/2(y+z)=65, x+1/2(x+y-z)=38​

Answer 1

Answer:

x= 24

y = 9

& z = 5

Step-by-step explanation:

1/3(x+y) + 2z = 21

=>x+y + 6z = 63 ------------ (1)

3x -1/2 (y+z) = 65

=> 6x - y -z = 130 -----------(2)

x +1/2(x+y-z ) = 38

=> 3x +y-z = 76 -----------(3)

adding equation 1 &2

7x + 5z = 193 -----------(4)

substrasting equation 3 from 1

-2x+7z = -13 ----------(5)

from equation 4& 5

10z + 49 z = 386 - 91

=> 59 z = 295

=> z = 5

putting the value of z in equation 5 , we get

-2x +35 = -13

=> 2x = 48

=> x = 24

putting the value of x & y in equation 1 we get

24 +y + 30 = 63

=> y = 9

HENCE

X= 24 , Y =9 & Z = 5