1
3(y-=)
=) = 2(2y— 6)
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sorry I cannot understand your question
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1
Answer:
Given, equation: $$3x - 2y = 6$$.
Now, to check whether (1,2) will lie on the line 3x−2y=6, we have to put the value of (x,y) in the given equation.
LHS =3(1)−2(2)=3−4=−1
=6 or RHS
Therefore, the point (1,2) will not lie on the line 3x−2y=6.
Now, at x=4, we have,
3(4)−2y=6
y=3
Again, 3x−2y=6
⇒ At x=0,y=−3 and at y=0,x=2
Therefore, table of points is:
x 0 2
y −3 0
So, graph of the given line is as:
solution
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