Question

1 = 36
4) The population of a certain town was 50,000. In a year, male population was increased
by 5% and female population was increased by 3%. Now the population became
52020. Then what was the number of males and females in the previous year?lol​

Answer 1

Answer:

Male population =x

Female population=y

x+y=50,000

y=50,000−x

x increased 5%

y increased 8%

(x+x×5%)+(y+y×8%)=53220

x+

100

5x

+y+

100

8y

=53220

100x+5x+100y+8y=5322000

as y=50,000−x

100x+5x+108(50,000−x)=5322000

105x−108x+5400000=5322000

5400000−5322000=3x

78000=3x

x=26000

y=50,000−x=50,000−26000

y=24000

∴ Male population=26000

Female population=24000

EXPLANATION :-

Hope It Helps You