1.36 g of HCl is dissolved in 200 cm3 of an aqueous solution . calculate its normality
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Normality = molarity x acidity
Molarity = (1.36*1000) / (36.5*200) = 0.1863
Normality = 0.1863 * 1 = 0.1863N
Molarity = (1.36*1000) / (36.5*200) = 0.1863
Normality = 0.1863 * 1 = 0.1863N
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