Question

(1) 38°,102°
measure of the third angle of traingles whose two angles are given below ​

Answer 1

Answer:

Given,

Angles = 38 and 102

Sum of all angles in triangle = 180

Let the third angle be x

ATP,

x + 38 + 102 = 180

x + 140 = 180

x = 180 - 140

X = 40

Answer 2

First 38+102=140

then 180-140=40 as all sides of an triangle add up to be 180

therefore answer is 40