Math, asked by AMRY, 7 months ago

(1-3a-3b) (3+4a+4b)

Answers

Answered by reshman46

1

Answer:

(1-3a-3b)(3+4a+4b)

= 3+4a+4b -9a-12a²-12ab-9b-11ab-12b²

=3-5a-5b-12a²-12b²-23ab

=3 -5a-5b-12a²-12b²-23ab

= -12(a²+b²)-5(a+b)+3-23ab

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