(1) 3a + 5b = 26; a + 5b = 22
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3a+5b=26
a+5b=22
By subtracting we get,
3a+5b=26
-a-5b=22(By changing signs)
=2a=4, therefore a=2
By substituting the value of a on any equation we get,
3×2+5b=26
,5b=26-6,
therefore b=4
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