Question

(1) 3a + 5b = 26; a + 5b = 22. please solve this simultaneous equation ​

Answer 1

Step-by-step explanation:

Linear equation...... =__=

3a +5b = 26........(1)

a + 5b = 22.........(2)

3a +5b = 26

a + 5b = 22

- - -

_____________

2a = 4

a = 2

Substitute value of a in (2)

a + 5b = 22

2 + 5b = 22

b = 4

so (a,b) => (2,4) is solution of equation

Answer 2

Answer:

3a + 5b = 26; .....(I)

a + 5b = 22 .....(II)

Subtracting (II) from (I)

2a = 4

⇒ a = 2

Putting the value of a = 2 in (II)

5b = 22 - 2 = 20

⇒b = 20/5

=4

Thus, a = 2 and b = 4.