Question

(1) 3a + 5b
26; a + 5b = 22 solve this simultaneous equation.​

Answer 1

Answer:

3a+5b=26.....................(1)

a+5b=22....................(2)

Subtracting (2) from (1), we get

3a+5b=26

a+5b=22

2a=4

2a=4

a=4/2

a=2

Substituting the value of a=2 in (2), we get.

a+5b=22

2+5b=22

5b=22-2

5b=20

b=20/5

b=4

So the value of a is 2 and the value of b is 4

I hope that I help you

Answer 2

Answer:

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