1/3abc from -2/3abc
Answers
Answered by
0
Step-by-step explanation:
7a+b+c=1……………….(1)
ab+bc+ca=1/3…………(2)
ab+c(b+a)=1/3
ab+c(1-c)=1/3
ab+c-c^2=1/3…………….(3)
From eq.(2)
b(a+c)+ca=1/3
b(1-b)+ca=1/3
ca+b-b^2=1/3………………..(4)
Again from eq.(2)
bc+ca+ab=1/3
bc+a(c+b)=1/3
bc+a(1-a)=1/3
bc+a-a^2=1/3………………….(5)
subtract eq.(4)from(3)
ab-ca-b+c+b^2-c^2=0
a(b-c)-1(b-c)+(b-c)(b+c)=0
(b-c)(a-1+b+c)=0
Either b-c=0 => b=c………………(6)
Suntract eq.(5)from(4).
ca-bc-a+b+a^2-b^2=0
c(a-b)-1(a-b)+(a-b)(a+b)=0
(a-b)(c-1+a+b)=0
Either a-b=0 => a =b………………(7)
From eq.(7) and (6).
a=b=c =k(let)
a : b : c = k : k : k or 1 : 1 : 1 , answer.
Answered by
1
Answer:
-2/3abc from 1/3abc
(-2/3-1/3)abc
-3/3 abc
-1 abc
Similar questions