Math, asked by riahabh2364, 9 months ago

-1-√3i/2 is a cube root of 1

Answers

Answered by Anonymous

1

Answer:

Yes

Step-by-step explanation:

${x}^{2} + x + 1 \: has \: imaginary \: roots \: and \: it \: is \: one \: of \: them$

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