Math, asked by adityanassa110405, 11 months ago

(1+3sinA-4sin^3A)/1-sinA = 1+2(sinA)^2

Answers

Answered by RockswithRAJU

5

Answer:

please let me know if you need any more than I

Answered by Pujan123

3

Answer:

R.h.s=(1+2sinA)^2

=1+4sinA+4sin^2

multiply by 1-sinA

=(1+4SinA+4Sin^2)1-sinA/1-sinA

=1+3sinA-4Sin^3/1-SinA

=L.H.S

Step-by-step explanation:

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