(1+3sinA-4sin^3A)/1-sinA = 1+2(sinA)^2
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Answered by
5
Answer:
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Answered by
3
Answer:
R.h.s=(1+2sinA)^2
=1+4sinA+4sin^2
multiply by 1-sinA
=(1+4SinA+4Sin^2)1-sinA/1-sinA
=1+3sinA-4Sin^3/1-SinA
=L.H.S
Step-by-step explanation:
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