Math, asked by haduthapa, 1 year ago

1×3tanx+1×cotx=5cosecx

Answers

Answered by iHelper
3
Hello!

3 tanx + cotx = 5 cosecx

⇒ 3 (sinx)² + (cos)² = 5 cosx

⇒ 3 sin²x + cos²x = 5 cosx

∵ sin²x = 1 - cos² x

⇒ 3 - 3 cos²x - cos²x = 5 cosx

Let " cosx " = t :

3 - 3t² - t² = 5t

⇒ 2t² + 5t - 3 = 0

⇒ (2t - 1).(t + 3) = 0

∴ t = 1 / 2 or t = - 3

Since, t = cosx > - 1
∴ - 3 is not included.

cosx = 1 / 2 ⇒ x = 60°

Cheers!
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