Math, asked by yasirahmedarafat2, 1 month ago

(1 +3w-w^2) (1+w-2w^2)​

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Answered by RUPAMCHAKRABORTY
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Answer:

If 1, w , w^2 are cube roots of unity , then find the value of (1 + 3w + w^2) + (1 + 3 - w^2)^4

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Given, 1 + 3w + w^2 + (1 + 3 - w^2 )^4 = 1 + 3w + w^2 + ( - w^2 + 4 )^4 = 1 + 3w + w^2 + w^8 - 16w^6 + 96w^4 - 256w^2 + 256 = w^8 - 16w^6 + 96w^4 - 255w^2 ...

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