(1/3x-1/4y)+3/4 yi=-3+5i...Guys need answer now immideatly drs...
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Step-by-step explanation:Given : Equation => (1/3x-1/4y)+3/4yi=-3+5 i
To find : Real values of x and y
Solution : Comparing the left-hand side real part with the right-hand side real part, we get
x/3 - y/4 = 3 ....(1)
Again, comparing left hand side imaginary part with right hand side we get
3y/4 = 5
From this we get value of y
y = 20/3
Substituting value of y in equation (1)
x/3 - 20/12 = 3
x/3 = 3 + 5/3
x/3 = 14/3
x = 14
Hence, real values of x and y are 14 and 20/3 respectively.
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1/3x -1\4y + 3/4 yi = -3+5i
Hence values of x and y are as follows..
X = -5 and Y = 20/3 or 6.6
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