Question

(1)
3x^3-4x^2+x-4 ..if X=-1 find its value

(2)
factorise x^2-x-12


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Answer 1

Answer:

1. -12
2. (x+3)(x-4)

Step-by-step explanation:

1) p(x)=3x³-4x²+x-4

Put x=-1

p(-1)=3(-1)³-4(-1)²-1-4= -3-4-1-4 =-12

2) x²-x-12

=x²+3x-4x-12

=x(x+3)-4(x+3)

=(x+3)(x-4)

Hope It Helps :)

Answer 2

Answer:

1) -12

Step-by-step explanation:

1)

3x^3-4x^2+x-4

put x=-1

3(-1)^3-4(-1)^2+(-1)-4

= 3*(-1)-4*(1)-1-4

= -3-4-1-4

= -12