Question

1/3x+y+1/3x_y=3/4; 1/2 (3x+y)_1/2 (3x_y)=1/8​

Answer 1

Answer:

1/3x+y + 1/3x-y =3/4

,1/2(3x+y) - 1/2(3x-y)=-1/8 find x and y

Let 3x+y =u

3x-y =v

1/u +1/v =3/4 (1) by multiplying 2 in equation (1)

1/2u- 1/2v=-1/8 (2)

1/2u + 1/2v =3/8 (1) by adding equation equation (1) and (2)

1/2u+1/2u = 2/8

2/2u = 1/4

1/u =1/4

u=4

by substituting u value in (1)

1/u +1/v =3/8

1/v+1/4 =3/4

1/v= 3/4-1/4=2/4=1/2

v=2 again solving the value of v and u

3x+y=4(3)

3x-y=2(4) by adding (3) and (4)

6x=6

x=1

by substitution x=1 in equation (3)

y=1

Answer

X= 1 and Y =1