{1}{3x+y} +{1}{3x-y} ={3}{4} and {1}{3x+} -{1}{3x-y} ={-1}{8} find the values
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{1}{3x+y} +{1}{3x-y} ={3}{4}
3x + y + = 3 x 4
3x+ 3x + y - y = 12
6 x +o = 12
6 x = 12
x=12²
x= 2
Step-by-step explanation:
the values is 2
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