Question

1/4,-1/2,1,-2...are in GP find t10​

Answer 1

Answer:

The value of t₁₀ is -85.25.

Step-by-step explanation:

The nth term of a GP is:

$T_{n}=\frac{a(r^{n}-1)}{r-1}$

The first terms is, a = 1/4.

The common ratio is, r = -2.

Compute the 10th term as follows:

$T_{10}=\frac{\frac{1}{4}((-2)^{10}-1)}{-2-1}=\frac{\frac{1}{4}\times1023}{-3}=-85.25$

Thus, the value of t₁₀ is -85.25.

Answer 2

Answer:

-6.5

Step-by-step explanation:

a= 1/4

d= -1/2-1/4= -3/4

a₁₀ or t₁₀= a+9d

a₁₀=1/4+9*-3/4

a₁₀=1/4-27/4

a₁₀= -26/4 = -13/2 = -6.5