Question

1/4, 1/3, 1/6, 1/12, 1/9 find the average​

Answer 1

Step-by-step explanation:

Average=165=0.3125

Step-by-step explanation:

Given \: data : \frac{1}{3},\frac{1}{2},\frac{1}{4},\frac{1}{6}Givendata:31,21,41,61

\begin{gathered} Average = \frac{sum\:of \: the\:terms }{Number \:of \:terms}\\=\frac{\frac{1}{3}+\frac{1}{2}+\frac{1}{4}+\frac{1}{6}}{4}\\=\frac{\frac{4+6+3+2}{12}}{4}\\=\frac{\frac{15}{12}}{4}\\=\frac{15}{12\times 4}\\=\frac{5}{16}\\=0.3125\end{gathered}Average=Numberoftermssumoftheterms=431+21+41+61=4124+6+3+2=41215=12×415=165=0.3125

Therefore,

\begin{gathered} Average = \frac{5}{16}\\=0.3125\end{gathered}Average=165=0.3125

Answer 2

Answer:

Step-by-step explanation:

Average = 47/48