1/4,-1 find a quadratic polynomial
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Answer:
4*(x)^2+3*x-1
Step-by-step explanation:
Let a and b be two arbitraty roots of a quadratic polynomial. Then the equation will be ( in terms of x which is a variable): x^2-(a+b)*x + a*b
Here, Let a= -1 and b= 1/4
So the equation is : x^2-(-1+1/4)*x +(-1)(1/4)
= x^2+(3/4)*x-1/4
On further simplification,
= 4*(x)^2+3*x-1
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