Question

1,4,16,64,...is a geometric progression with common ratio=4
The 10th term of this geometric progression=?

Answer 1

Answer: 5461

Step-by-step explanation:

The 10th term of this geometric progression=1×$4^{10-1}$=262144

The sum of the first 6 terms of this geometric progression= 1×(1-$4^{6+1} divided by(1-4)=5461$

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