1.
4х + Зу = 17
Зx- 4у +6= 0
Answers
Answered by
1
Answer: x=10 and y = 9
Step-by-step explanation:
4х + Зу = 17 *4 ----(1)
Зx- 4у = -6 *3 ------(2)
16x+12y = 68
9x -12y = -18
25x= 50
x=2
Sub x in eq 2
6 -4y = -6
-4y = -6-6
-4y = -12
y=3
Answered by
1
Answer:
x=2 y=3
Step-by-step explanation:
Зx- 4у +6= 0
Зx- 4у = 0 -6
Зx- 4у = -6
multiply by 4
4×Зx- 4×4у = -6×4
12x-16y=-24 equation 1
4х + Зу = 17
multiply by 3
3×4х + 3×Зу = 17×3
12x+9y=51 equation 2
subtract equation 1 from equation 1
12x+9y=51- (12x-16y=-24)
12x-12x+9y+16y=51+24
0+25y=75
y=75/25
y=3
putting y=3 in 4х + Зу = 17
4х + З×3 = 17
4x+9=17
4x=17-9
4x=8
x=8/4
x=2
check
Зx- 4у +6=0
3×2-4×3+6=0
6-12+6=0
0=0
LHS=RHS
4х + Зу = 17
4×2+3×3=17
8+9=17
17=17
LHS=RHS
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