Math, asked by ss452781, 11 days ago

(1/4^)-2×(1/2)^-3×(8^4)​

Answers

Answered by NischaySinha
0

Step-by-step explanation:

(

4

1

)

−2

−3(8)

3

2

(4)

0

+(

16

9

)

2

−1

=

3

16

Step-by-step explanation:

Given : Expression ( \frac{1}{4})^{ - 2}- 3(8)^{ \frac{2}{3}}(4)^{0} +( \frac{9}{16})^{ \frac{-1}{2}}(

4

1

)

−2

−3(8)

3

2

(4)

0

+(

16

9

)

2

−1

To find : Simplify the expression ?

Solution :

Expression ( \frac{1}{4})^{ - 2}- 3(8)^{ \frac{2}{3}}(4)^{0} +( \frac{9}{16})^{ \frac{-1}{2}}(

4

1

)

−2

−3(8)

3

2

(4)

0

+(

16

9

)

2

−1

Factor the bracket terms into power,

={4}^{2} - 3( {2}^{3} ) {}^{ \frac{2}{3} } \times 1 + ( \frac{3}{4} ) {}^{2 \times ( \frac{ - 1}{2}) }=4

2

−3(2

3

)

3

2

×1+(

4

3

)

2×(

2

−1

)

=16 - 3 \times {2}^{2} + ( \frac{3}{4} ) {}^{ - 1}=16−3×2

2

+( 4

3 )

−1

=16 - 12 + \frac{4}{3}=16−12+

3

4

=4 + \frac{4}{3}=4+

3

4

=\frac{12 + 4}{3}=

3

12+4

=\frac{16}{3}=

3

16

Therefore, ( \frac{1}{4})^{ - 2}- 3(8)^{ \frac{2}{3}}(4)^{0} +( \frac{9}{16})^{ \frac{-1}{2}}=\frac{16}{3}(

4

1

)

−2

−3(8)

3

2

(4)

0

+(

16

9

)

2

−1

=

3

16

#Learn more

[{(-1/4)^2}^-1]^-2 simplify

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