Question

(1,4) ; (-2,3) are conjugate points with respect to X^2 + Y^2= k then k=?​

Answer 1

The value of k will be 10.

Solution:

Given that the points (4, 2) and (-2, 3) are conjugate.

Now

x (2) + y (2)  = k

(x,y) a2 (x2 - y2) are conjugate points then S 1,2 = 0

So,

x1x2 + y1y2 = k

So when we substitute values:

(1) (- 2) + (4) (3) = k

- 2 +12 = k

k = 10

Thus, the value of k =10

#SPJ3