Question

(- 1/4) ^ 3 ÷(3/8) ^ - 2​

Answer 1

$( { \frac{ - 1}{4}) }^{-3} \div ( { \frac{3}{8}) }^{ - 2}$

$\frac{ 4 \times 4 \times 4}{-1\times -1 \times -1} \div ( { \frac{8}{3} )}^{ 2}$

$\frac{ 64}{-1} \times \frac{3 \times 3}{8 \times 8}$

-9/1

-9

Answer 2

Answer :-

$\rm \: The \: answer \: of \: this \: question \: is \: \bf \: -9\:{\red\bigstar}$

Step-by-step-Explaination :-

$\rm {\bigg(} \dfrac{ - 1}{4}{ \bigg)}^{ - 3} \div { \bigg(} \dfrac{3}{8}{ \bigg)}^{ - 2}$

If we need to simplify it , we need to make the power positive , but to do it we need to flip the fraction (i.e. Making Denominator as Numerator and Numerator as Denominator).

$\rm : \implies{\bigg(} \dfrac{ -4}{1}{ \bigg)}^{ 3} \div { \bigg(} \dfrac{8}{3}{ \bigg)}^{ 2}$

$\rm : \implies \: \dfrac{ - 4 \times - 4 \times - 4}{1 \times 1 \times 1} \div \dfrac{8 \times 8}{3 \times 3}$

$\rm : \implies \: \dfrac{ - 64}{1} \div \dfrac{64}{9}$

$\rm : \implies \: \cancel\dfrac{- 64}{1} \times \cancel \dfrac{9}{64}$

$\rm : \implies \: \dfrac{ - 1 \times 9}{1 \times 1}$

$\rm : \implies \: \dfrac{ -9}{1}$

$\rm : \implies \: -9\:{\green\bigstar}$