1/4,3/4,1,5/4....in this AP which term is 17/4?
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In A.p, we have a formula a+(n-1)d =Tn. Here a is the first term, Tn is nth term, d is the common difference preceding to the next term= t2-t1= t3-t2= 3/4-1/4=5/4-3/4=1/2. Tn = 17/4. Now, a= 1/4(First term) , n is the nth term=?, d=1/2, Tn =17/4. Now, according to formula, 1/4+(n-1) 1/2= 17/4. 1/4 +n/2-1/2=17/4. n/2-1/2= 17/4-1/4. n/2-1/2= 4, (n-1)/2= 4. n-1= 4×2. n-1= 8, n=8+1, n=9. Now we got n= 9, i.e 9th term of 1/4,3/4,5/4...... is 17/4. Hence the final answer is 9th term. Hope this helps you.
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