Question

1+4/3+5/3+..... to 58 terms​

Answer 1

Answer:

write 1 equals to 3 by 3 so we get the series 3 by 3 + 4 by 3 + 5 by 3 and so on 58 terms so it will take 1 by 3 common on whole series then bracket we get 3 + 4 + 5 + 6 is goes to 58 term and we know our series start from 3 so our 58 term is 60 sunao with simply apply the formula of sum of n natural number that is N (N + 1) by 2 now we're putting here n equals to 60 because we find 1 to 60 natural numbers sum so we get the sum of 1 to 60 natural number is 1830 now we know our series a start from 3 so we subtract 3 from 1830 and finally get 1827 and on the starting we take one by three common so simply we divide 1827by 3 no finally we get the answer of this series is 609