(1) (4/9)4×(4/9)7=(4/9)2n-1 find n in exponential form
(2) (5)2n+1×25=(5)3 find n in exponential form
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Answers
Answer:
Step-by-step explanation:Here are some solved examples on exponents using the laws of exponents.
1. Evaluate the exponent:
(i) 5-3
(ii) (1/3)-4
(iii) (5/2)-3
(iv) (-2)-5
(v) (-3/4)-4
We have:
(i) 5-3 = 1/53 = 1/125
(ii) (1/3)-4 = (3/1)4 = 34 = 81
(iii) (5/2)-3 = (2/5)3 = 23/53 = 8/125
(iv) (-2)-5 = 1/(-2)-5 = 1/-25 = 1/-32 = -1/32
(v) (-3/4)-4 = (4/-3)4 = (-4/3)4 = (-4)4/34 = 44/34 = 256/81
2. Evaluate: (-2/7)-4 × (-5/7)2
Solution:
(-2/7)-4 × (-5/7)2
= (7/-2)4 × (-5/7)2
= (-7/2)4 × (-5/7)2 [Since, (7/-2) = (-7/2)]
= (-7)4/24 × (-5)2/72
= {74 × (-5)2}/{24 × 72 } [Since, (-7)4 = 74]
= {72 × (-5)2 }/24
= [49 × (-5) × (-5)]/16
= 1225/16
3. Evaluate: (-1/4)-3 × (-1/4)-2
Solution:
(-1/4)-3 × (-1/4)-2
= (4/-1)3 × (4/-1)2
= (-4)3 × (-4)2
= (-4)(3 + 2)
= (-4)5
= -45
= -1024.
4. Evaluate: {[(-3)/2]2}-3
Solution:
{[(-3)/2]2}-3
= (-3/2)2 × (-3)
= (-3/2)-6
= (2/-3)6
= (-2/3)6
= (-2)6/36
= 26/36
= 64/729
5. Simplify:
(i) (2-1 × 5-1)-1 ÷ 4-1
(ii) (4-1 + 8-1) ÷ (2/3)-1
Solution:
(i) (2-1 × 5-1)-1 ÷ 4-1
= (1/2 × 1/5)-1 ÷ (4/1)-1
= (1/10)-1 ÷ (1/4)
= 10/1 ÷ 1/4
= (10 ÷ 1/4)
= (10 × 4)
= 40.
(ii) (4-1 + 8-1) ÷ (2/3)-1
= (1/4 + 1/8) ÷ (3/2)
= (2 + 1)/8 ÷ 3/2
= (3/8 ÷ 3/2)
= (3/8 ÷ 2/3)
= 1/4
6. Simplify: (1/2)-2 + (1/3)-2 + (1/4)-2
Solution:
(1/2)-2 + (1/3)-2 + (1/4)-2
= (2/1)2 + (3/1)2 + (4/1)2
= (22 + 32 + 42)
= (4 + 9 + 16)
= 29.
7. By what number should (1/2)-1 be multiplied so that the product is (-5/4)-1?
Solution:
Let the required number be x. Then,
x × (1/2)-1 = (-5/4)-1
⇒ x × (2/1) = (4/-5)
⇒ 2x = -4/5
⇒ x = (1/2 × -4/5) = -2/5
Hence, the required number is -2/5.
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Answer:
Step-by-step explanation:drfdcxtyddsf