Math, asked by shakthinadar63, 2 months ago

1/4(a+b) cube - 9/16(2a-b) square​

Answers

Answered by vkr12867
1

Answer:

1/4a³ +1/4b³ +3/4a²b +3/4ab² -9/2a³ +9/16b³ +27/4a² -27/8ab²

Step-by-step explanation:

1/4(a+b)³ - 9/16(2a-b)²

1/4{a³ +b³ +3ab(a+b)} -9/16{(2a)³ -(b³)-3(2a)(b)(2a-b)}

1/4(a³ +b³ +3a²b + 3ab²) -9/16{8a³ -b³ -6ab(2a-b)}

(1/4a³ +1/4b³ +3/4a²b +3/4ab²) -9/16(8a³ -b³ -12a² +6ab²)

1/4a³ +1/4b³ +3/4a²b +3/4ab² -9/2a³ +9/16b³ +27/4a² -27/8ab²

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Answered by santum
1

Step-by-step explanation:

1/4 (a+b) ^3 - 9/16 (a-b)^2

(a^3 + b^3 + 3a^2b + 3ab^2)/4 - 9(a^2 + b^2 -2ab)/16

(lcm = 16)

(4a^3 + 4b^3 + 12a^2b + 12ab^2 - 9a^2 - 9b^2 -18ab)/16

please folow me

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