1/4 and -1zeroes of the polynomials p(x)=4x2+3x-1
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Answer:
p(x)=4x^2+3x-1
p(1/4)=4(1/4)^2+3(1/4)-1
=4(1/16)+3/4-1
=4/16+3/4-1
=1/4+3/4-1
=1+3-4/4
=0
p(-1)=4(-1)^2+3(-1)-1
=4-3-1
=1-1
=0
Therefore,the 1/4,-1 are the zeros of the given polynomial..
hope it's helpful!!
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