Question

1.4 Calculate the amount of carbon dioxide that could be produced when: (i) 1 mole of carbon is burnt in air. (ii) 1 mole of carbon is burnt in 16 g of dioxygen. (iii) 2 moles of carbon are burnt in 16 g of dioxygen. PLZ solve this question friends in systematic way​

Answer 1

(i) 1 mole of carbon is burnt in air.

C+O

2

→CO

2

1 mole of C produces 1 mole of CO

2

which corresponds to 44 g of CO

2

.

(ii) 1 mole of carbon is burnt in 16 g of dioxygen.

16 g of dioxygen corresponds to

32

16

=0.5 moles.

Here, dioxygen is the limiting reagent.

It will produce 0.5 moles of CO

2

which corresponds to 0.5×44=22 g of CO

2

.

(iii) 2 moles of carbon are burnt in 16 g of dioxygen.

16 g of dioxygen corresponds to

32

16

=0.5 moles.

Here, dioxygen is the limiting reagent.

It will produce 0.5 moles of CO

2

which corresponds to 0.5×44=22 g of CO

2

.