Question

1,4-dibromobutane on reaction
with Zn in the presence of Nal catalyst
forms
O Cyclopentane
O Cyclobutane
O 1,3-butadiene
Cyclopropane​

Answer 1

Answer: Cyclobutane is formed when 1,4-dibromobutane on reaction with Zn in the presence of Nal catalyst.

Explanation:

• This is an example of elimination reaction.

• α- and δ-dihalides when treated with zinc, they form cycloalkanes. Thus, 1,4-dibromobutane becomes cyclobutane.

Answer 2

Solution:

cyclobutane is correct answer.

Explanation:

The derivative is 1,4 dibromobutane. This on reaction with Zn metal gives cyclobutane.