1.4 g of dolomite was dissolved (CaCO3 and MgCO3) was dissolved in 200 ml of 0.2 N HCl solution. After the reaction was complete , the resulting solution was diluted to 250 ml and 10 ml of this solution required 12 ml of 0.1 N NaOH solution for complete neutralization. Calculate the percentage of composition of the mixture
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i dont know the answer of the question
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something is wrong in your question
Explanation:
equivalent of 10ml is 1.2
equivalent of 250 = 30
equivalent of acid initial = 40
equivalent of acid reacted = 10
equivalent of caco3 + equivalent of mgco3 = 10
moles+moles=0.01
w/100 + 1.4-w/84 = 0.01
140-16w=84
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