1.4 g of organic substances burned in excess of air(o2)gave 4.4g of co2 and 1.8g of h2o .find emperical formula
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Answer:
My answer is according to 30g of organic substances
Explanation:
Moles of C= moles of CO
2
=
44
0.44
=0.01 moles
Moles of H=2×moles of H
2
O=2×
18
0.18
=0.02 moles
Weight of oxygen = ( 0.30 - weight of carbon and hydrogen ) = (0.3−0.01×12−0.02×1)=0.16 gm
Moles of O=
16
0.16
=0.01 moles
Empirical formula =CH
2
O
Empirical formula mass =30 gm
n=
30
60
=2
Formula=(CH
2
O)
n
=C
2
H
4
O
2
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