Question

1.4 g of sample of chalk (CaCO3) containing clay as impurity were treated with excess of dilute HCl . volume of CO2 evolved when measured at 15°C and 768 mm pressure was 282 cm3 . calculate the % purity of the sample

Answer 1

Dear frnd

Using ideal gas law, PV=nRT;   Converting P in atm, V in litres and T in k n=0.01196~ 0.012

1 mole of CaCO3= 1 mole of CO2.

Therefore number of moles of CaCO3=0.012.

gram  molecular mass of CaCO3= 0.012x100= 1.196.

% purity=100-( (1.4-1.196)/1.54x100)= 100-13.246=86.754

Answer 2

Explanation:

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