1.4 gram nitrogen is present in 500mL of its aqueous solution.Compute the molarity of the solution.
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Answer:
Molarity=number of moles of the solute/volume of the solution in liter
Explanation:
number of mole=1.4/14=0.1mole/gram
volume of solution=500*10^-3 l
molarity=0.1/500*10^-3=0.2M
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