Chemistry, asked by harishchandraprajapa, 3 months ago

1.4 gram nitrogen is present in 500mL of its aqueous solution.Compute the molarity of the solution.

Answers

Answered by mkmadhankumar10

4

Answer:

Molarity=number of moles of the solute/volume of the solution in liter

Explanation:

number of mole=1.4/14=0.1mole/gram

volume of solution=500*10^-3 l

molarity=0.1/500*10^-3=0.2M

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