Question

1
4. In triangle ABC, if <A - <B= 42
degree and <B - <C = 21 degree,
then <B = ? *
0 95 degree
53 degree
32 degree
63 degree​

Answer 1

Answer:

957575747737₹8788465

Answer 2

Answer:

\( { \frac{d}{dx}(sin^{-1}x) = \frac{1}{\sqrt{1 – x^2}}} \)

Also, \( { \frac{d}{dx}(cos^{-1}x) = \frac{-1}{\sqrt{1 – x^2}}} \)

\( { \frac{d}{dx}(tan^{-1}x) = \frac{1}{1 + x^2}} \)

\( { \frac{d}{dx}(cosec^{-1}x) = \frac{-1}{mod(x).\sqrt{x^2 – 1}}} \)

And, \( { \frac{d}{dx}(sec^{-1}x) = \frac{1}{mod(x).\sqrt{x^2 – 1}}} \)

\({ \frac{d}{dx}(cot^{-1}x) = \frac{-1}{1 + x^2}} \)