Math, asked by ellietorres200, 4 months ago

1/4 of the school playground is used for basketball court and 3/8 for a football field what fraction of the playground is left for the swings and play equipment

Answers

Answered by harsh9168
2

Answer:

Given :

Part of the ground used by the students for basket ball court = \frac{1}{4}

4

1

Part of the ground used by the students for soccer field = \frac{3}{8}

8

3

To Find :

Part of the ground left for swing and playground equipment =?

Solution :

Since the total area of the playground will be = length of playground \times× breadth of play ground

Let the total area be A.

Now the area used = area used for basket ball court + area used for soccer field

=\frac{1}{4} A + \frac{3}{8} A

4

1

A+

8

3

A

=\frac{5}{8}A

8

5

A

And the area left for swings and equipments = A -\frac{5}{8} A = \frac{3}{8}AA−

8

5

A=

8

3

A

So, the part of total area left for swings and equipments is \frac{3}{8}

8

3

of the total area

Step-by-step explanation:

I hope it help you

Answered by bhowmik2018piu
2

Step-by-step explanation:

1/4 of the school’s playground is used for basketball court and 3/8 for a football field.

let the whole fraction is 1

so, fraction of the playground is left for the swings and play equipment is=

1-1/4 -3/8

= (8-2-3)/8

= 3/8

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