Question

(1) 40 m
(2) 100 m
(3) 140 m
(4) 400 m
11. The length of a rectangular field is double its width. If the width is 100 m, what will be its area?
)
(
) sq
12. The area of a square court is 196 sq m. The perimeter is
(1) 40 m
(2) 60 m
(3) 50 m
(4) 56 m​

Answer 1

Solution : 11

$\bf \: \underline{Given} :$ ↴

$\sf \: The \: length \: of \: a \: rectangular \: field \: is \: double \: its \: width.$

$\sf \: Width \: of \: the \: rectangular \: field = 100 \: meter.$

$\bf \: \underline{To \: find} :$ ↴

$\sf \: We \: have \: to \: find \: it's \: area.$

$\bf \: \underline{ \underline{ So, \: Let's \: Start}}$

$\sf \: If \: the \: length \: of \: the \: rectangular \: field \: is \: double \: its \: width.$

$\sf \: Then,$

$\sf \: Length \: of \: the \: field = 100 \: meter + 100 \: meter$

$\sf \: So, \: Length \: of \: the \: field = 200 \: meter$

$\underline{ \sf \: Now, \: we \: will \: find \: the \: area }$

$\sf \: As \: we \: know \: that,$

$\boxed{ \pink{ \sf \: Area \: of \: Rectangle = (Length \times Breadth)}}$

$\sf \: Putting \: the \: values,$

$\sf \: Area \: of \: Rectangle = (200 \times 100)$

$\red{ \sf So, \: area \: of \: rectangular \: field = 20000 \: m^{2}}$

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Solution - 12

$\bf \: \underline{Given} :$ ↴

$\sf \: The \: area \: of \: a \: square \: court = 196 \: m ^{2}$

$\bf \: \underline{To \: find} :$ ↴

$\sf \: We \: have \: to \: find \: it's \: perimeter.$

$\bf \: \underline{\underline{So, \: let's \: find \: it }}$

$\sf \: We \: know \: that,$

$\sf \: Area \: of \: square = Side ^{2}$

$\sf \: \sqrt{196} = Side ^{2}$

$\sf \: 14 = Side ^{2}$

$\sf \: Hence, \: side \: (S) = 14 \: meter$

$\sf \: Now, \: we \: have \: to \: find \: the \: perimeter.$

$\sf \: As \: we \: know,$

$\boxed{ \pink{\sf \: Perimeter \: of \: square = 4 \times Side}}$

$\sf \: So,$

$\sf \longrightarrow \: 4 \times 14$

$\sf \longrightarrow \: 56 \: meter$

$\sf \: \red{So, \:perimeter \: of \: the \: square = 56 \: meter.}$