1. 40% of the students in a college play basketball, 34% of the students play tennis and the number of students
who play both the games is 234. The number of students who neither play basketball nor tennis is 52%. Find
the student population in the college.
(a) 800
( 1050
(c) 900
(d) 850
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Given:
40% of the students in a college play basketball, 34% of the students play tennis and the number of students who play both the games is 234
To find:
Total students in the college
Solution:
n( basketball) = 40%
n(tennis) = 34%
n(basketball ∪ tennis)' = 52%
n(basketball ∪ tennis) = 100-52 = 48%
we know that:
n(basketball ∪ tennis) = n( basketball)+n(tennis)-n(basketball ∩ tennis)
48% = 40% + 34% - n(basketball ∩ tennis)
n(basketball ∩ tennis) = 74% - 48%
n(basketball ∩ tennis) = 26%
as per the question:
26% = 234
1% = 9
100% = 900
Hence, the total student in the college is 900
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