Math, asked by Anonymous, 4 months ago

1) 40% passengers from a train got down at station A, 60% of the remaining
passengers got down at station B. If there were still 540 passengers in the train
how many passengers were there before station A provided no one boarded the train
at station A and station B?
2) The value of a car depreciates 20% every year. If after two years the price of a car
is 208000, find its original price.
please answer these two questions fast,
it's urgent​

Answers

Answered by swetamohanty573
1

Answer:

Let The Number Of Passengers = x

Now Passengers Remaining At Station A = x-40/100*x = 3x/5

Now Passengers Remaining At Station B = 3x/5-60/100*3x/5 = 3x/5 - 9x/25

=> 6x/25

So This Equals 540

So

6x/25 = 540

x = 540*25/6 =  2250

So There Were Total 2250 Passengers In The Train

2It is given that if car depreciates 20% every year, then after two years the value of car is rupees 420000. Therefore the original price of the car is rupees 656250.

Answered by HorridAshu
0

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Let The Number Of Passengers = x

Now Passengers Remaining At Station A = x-40/100*x = 3x/5

Now Passengers Remaining At Station B = 3x/5-60/100*3x/5 = 3x/5 - 9x/25

=> 6x/25

So This Equals 540

So

6x/25 = 540

x = 540*25/6 =  2250

So There Were Total 2250 Passengers In The Train

2It is given that if car depreciates 20% every year, then after two years the value of car is rupees 420000. Therefore the original price of the car is rupees 656250.

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