1.435g of AgCl was obtained by treating 1.70g of AgNo3 with excess of NaCl .find the equivalent weight of No3.
Given the equivalent weight of Ag108 and Cl 35.5
Answers
Answered by
0
Answer:
ndjdcnbgdjfzfjkgfxbmloo
Explanation:
tjffgjv d0000000000000))))
Similar questions