1.47 litre of a gas is collected over water at 30∘C and 744mm of Hg . If the gas weight 1.98g and vapour pressure of water at 30∘C is 32mm , What is the molecular weight of gas?
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w = 1.98g
V = 1.47 litre
T = 303 K
P = 744 - 32 = 712mm = 712760 atm
Since For dry gas , PV=wmRT
=712760×1.47=1.98m×0.0821×303
∴m=35.76g
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Answer:
35.76 g
Explanation:
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